Contact: 7697517555
- Study Anytime, Anywhere through Our Mobile App & Web Portal
- 1000+ Video Lectures by CAT/XAT Topper Faculties
- 400+ Hours content of CAT Preparation Videos
- 9000+ Questions in Online CAT Coaching Course
- 200+ Topic Based Tests (50+ Basic, 50+ Moderate & 50+ Advanced Level)
- 20+ CAT Mocks (Pro CATs – Best Online Tests Series for CAT)
- 10+ Mock OMETs (Online Test Series for SNAP, NMAT, IIFT, XAT, TISS, CMAT)
- Online Doubt Solving on One – to – One basis
- GD-PI-WAT Online Preparation Material
Get access to the detailed solutions to the previous years questions asked in IIFT exam
Area of shaded region = area of semicircle on BC + area of semicircle of AC - area of unshaded semicircle regions
Area of unshaded semicircle regions = area of semicircle on AB - area of triangle ABC
Given,
AB = 50, BC = 14
In triangle ABC,
Solving we get, AC2+BC2=AB2
AC = 48
Area of unshaded semicircle regions = π (25)2 -1/2 X 48 X 14 = 625π - 336
Area of shaded region = 576π + 49π - 625π + 336 = 336
The answer is option A.